How many geometrical isomers and stereoisomer | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For the square planar complex $[Pt(abcd)]^+$,the number of geometrical isomers is $3$. These are the arrangements where pairs of ligands are trans

Vedclass · Accepted Answer

$3$ and $30$

Vedclass · Answer

(B) For the square planar complex $[Pt(abcd)]^+$,the number of geometrical isomers is $3$. These are the arrangements where pairs of ligands are trans to each other: $(a,b), (a,c), (a,d)$.For the octahedral complex $[Pt(abcdef)]$,the number of geometrical isomers is $15$. Since all ligands are different,each geometrical isomer exists as a pair of enantiomers (optical isomers). Therefore,the total number of stereoisomers is $15 	imes 2 = 30$.

How many geometrical isomers and stereoisomers are possible for $[Pt(NO_2)(NH_3)(NH_2OH)(Py)]^+$ and $[Pt(Br)(Cl)(I)(NO_2)(NH_3)(Py)]$ respectively?

Similar Questions

The two compounds pentaamminesulphatocobalt $(III)$ bromide and pentaamminesulphatocobalt $(III)$ chloride represent:

Which of the following will exhibit optical activity?

Calculate the total number of stereoisomers for the octahedral complex $[Fe(F)(Cl)(Br)(I)(NH_3)(H_2O)]^-$.

Draw the structures of the geometrical isomers of $[Fe(NH_3)_2(CN)_4]^-$.

What will be the value of $x$ in $Fe^{x+}$,if the magnetic moment,$\mu=\sqrt{24} \ BM$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module